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At 27^{\circ} \mathrm{C} two moles of an ideal monoatomic gas occupy a volume \mathrm{\mathrm{V}}. The gas expands adiabatically to a volume \mathrm{\mathrm{2V}}.The final temperature of the gas is:
 

Option: 1

150 \mathrm{~K}


 


Option: 2

162 \mathrm{~K}
 


Option: 3

173 \mathrm{~K}
 


Option: 4

189 \mathrm{~K}


Answers (1)

best_answer

In case of adiabatic change

\mathrm{P V^\gamma =\text { constant with } P V=\mu R T }

\mathrm{\text { so that } T_1 V_1 ^\gamma =T_2 V_2 ^\gamma-1 }

\mathrm{\text { i.e. } \quad 300 \times V^{2 / 3}=T(2 V)^{2 / 3} \text { or } T=300 /(2)^{2 / 3}=189 \mathrm{~K}}





 

Posted by

Ajit Kumar Dubey

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