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At what temperature average kinetic energy of the molecule of a perfect gas be doubled than  that at 20 oC?

Option: 1

300oC


Option: 2

303oC


Option: 3

313 oC


Option: 4

333 oC


Answers (1)

best_answer

Here, 

T1 = 20 0C  = 293K

As average kinetic energy of gas molecule is proportional to the absolute temperature of the gas, the required temperature,

T_{2}=2_{}\times 293 = 586K

     = (586-273 ) ^{0}C

     = 313 ^{0}C

Posted by

himanshu.meshram

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