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Bond energy varies from \mathrm{N}_2{ }^{-} to  \mathrm{N}_2{ }^{+}

Option: 1

Bond energy \mathrm{N}_2{ }^{-}> Bond energy \mathrm{N}_2{ }^{+}
 


Option: 2

Bond energy \mathrm{N}_2< Bond energy \mathrm{N}_2{ }^{+}
 


Option: 3

Bond energy \mathrm{N}_2{ }^{-}= Bond energy \mathrm{N}_2{ }^{+}
 


Option: 4

Can't be predicted.


Answers (1)

best_answer

Bond energy of \mathrm{N}_2^{+}= Bond energy of \mathrm{N}_2^{-}

because bond order is same in both the species.

[However, \mathrm{N}_2{ }^{+}is slightly more stable than \mathrm{N}_2{ }^{-}

as antibonding electrons number is higher in

\mathrm{N}_2{ }^{-}$than in $\mathrm{N}_2{ }^{+}.]

Posted by

Divya Prakash Singh

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