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Both radii of curvature of a convex lens are 20 \mathrm{~cm} and refractive index of the material of the lens is 1.5. Rays parallel to the axis of the lens will converge at

Option: 1

10 \mathrm{~cm}


Option: 2

20 \mathrm{~cm}


Option: 3

30 \mathrm{~cm}


Option: 4

40 \mathrm{~cm}


Answers (1)

best_answer

\mathrm{\text { As } \frac{1}{f}=(\mu-1)\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)}
\mathrm{ \therefore \frac{1}{f}=(1.5-1)\left(\frac{1}{20}-\frac{1}{-20}\right)=\frac{0.5 \times 2}{20}=\frac{1}{20}}

\mathrm{ or \, \mathrm{f}=20 \mathrm{~cm}\, i.e., \text{rays will converge at} 20 \mathrm{~cm}} from the optical centre of the lens.

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rishi.raj

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