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  • By what factor does the average velocity of a gaseous molecule increase when the temperature (in Kelvin) is doubled?Option: 1 2.0<div c

By what factor does the average velocity of a gaseous molecule increase when the temperature (in Kelvin) is doubled?

Option: 1

2.0


Option: 2

2.8


Option: 3

4.0


Option: 4

1.4


Answers (1)

best_answer

From Kinetic theory of gases

Average speed of gas molecules -

V_{avg}=\sqrt{\frac{8RT}{\pi M}}

where

M- Molecular Mass , R- Gas Constant , T- Temperature

 

 Average velocity V_{avg}= \sqrt {\frac{8RT}{\pi M}}

For the same gas at two different temperatures,

\therefore \frac{V_{2}}{V_{1}}= \sqrt {\frac{T_{2}}{T_{1}}}

\because T_{2}=2T_{1}\;\; \Rightarrow \frac{V_{2}}{V_{1}}=\sqrt 2 =1.41

Hence, Option 4 is correct.

Posted by

Suraj Bhandari

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