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  • Choose the balanced reaction for the disproportionation of  in alkaline medium:<div c

Choose the balanced reaction for the disproportionation of \mathrm{XeO}_3 in alkaline medium:

Option: 1

\begin{aligned} & \mathrm{XeO}_3+\mathrm{OH}^{-} \rightarrow \mathrm{Xe}(\mathrm{g})+\mathrm{XeO}_6^{4-}+\mathrm{O}_2+\mathrm{H}_2 \mathrm{O} \\ \end{aligned}


Option: 2

\begin{aligned} & \mathrm{XeO}_3+2 \mathrm{OH}^{-} \rightarrow \mathrm{Xe}(\mathrm{g})+\mathrm{XeO}_6^{4-}+\mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O} \\ \end{aligned}


Option: 3

\begin{aligned} & 2 \mathrm{XeO}_3+4 \mathrm{OH}^{-} \rightarrow \mathrm{Xe}(\mathrm{g})+\mathrm{XeO}_6^{4-}+\mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O} \\ \end{aligned}


Option: 4

\begin{aligned} & \mathrm{XeO}_3+2 \mathrm{OH}^{-} \rightarrow \mathrm{Xe}(\mathrm{g})+\mathrm{XeO}_6^{4-}+\mathrm{O}_2+\mathrm{H}_2 \mathrm{O} \end{aligned}


Answers (1)

best_answer

The unbalanced reaction is : \mathrm{XeO}_3+\mathrm{OH}^{-} \rightarrow \mathrm{Xe}(\mathrm{g})+\mathrm{XeO}_6^{4-}+\mathrm{O}_2

Balancing the atoms and charge:2 \mathrm{XeO}_3+4 \mathrm{OH}^{-} \rightarrow \mathrm{Xe}(\mathrm{g})+\mathrm{XeO}_6^{4-}+\mathrm{O}_2

Adding water to balance hydrogen: 2 \mathrm{XeO}_3+4 \mathrm{OH}^{-} \rightarrow \mathrm{Xe}(\mathrm{g})+\mathrm{XeO}_6{ }^{4-}+\mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O}

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SANGALDEEP SINGH

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