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  • Choose the correct option related to the specific heat at constant volume <strong

Choose the correct option related to the specific heat at constant volume C_{V}

Option: 1

C_V=\frac{1}{2} f R


Option: 2

C_V=\frac{R}{Y-1}


Option: 3

C_V=\frac{C_p}{Y}


Option: 4

All of these


Answers (1)

C_p-C_r=R

Dividing by C_V, we get

\begin{aligned} & Y-1=\frac{R}{C_V} \\ & C_V=\frac{R}{Y-1} \end{aligned}

Further, 

\begin{aligned} & U=\frac{f}{2} R T \\ & C_V=\frac{d U}{d T}=\frac{f}{2} R \end{aligned}

We know that, 

\begin{aligned} & \gamma=\frac{C_p}{C_V} \\ & C_V=\frac{C_p}{y} \end{aligned}

Posted by

Sumit Saini

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