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Consider a car with mass that is accelerating on a level smooth road due to a single force . The power delivered to the car remains constant and is denoted as . At a particular instant, the car has a velocity . How far must the car travel in order for its velocity to double?

Option: 1

\frac{7}{3 K} m u^3


Option: 2

\frac{8}{3 K} m u^3


Option: 3

\frac{5}{3 K} m u^3


Option: 4

\mathrm{None \, \, of \, \, these}


Answers (1)

best_answer

\text { Power }=\text { force } \times \text { velocity }

                 =p \times u \text { (where } p=\text { force) }

              k=m u^2 \frac{d u}{d x}

d x=m u^2 \frac{d u}{k}

                                                         \int_0^x d x=\int_u^{2 u} m u^2 \frac{d u}{k}

x=\frac{7}{3 p} m u^3

Posted by

avinash.dongre

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