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Decomposition of \mathrm{H}_2 \mathrm{O}_2 \text { (aq)}  takes place as:

2 \mathrm{H}_2 \mathrm{O}_2(\mathrm{aq}) \rightarrow 2 \mathrm{H}_2 \mathrm{O}(\mathrm{l})+\mathrm{O}_2\text{(g)}

It is given that 45 L volume is occupied by 1 mol of the gas and 200 mL of xM solution of \mathrm{H}_2 \mathrm{O}_2 forms 10 L oxygen. Find x.

Option: 1

0.2


Option: 2

0.02


Option: 3

2.20


Option: 4

2.5


Answers (1)

best_answer

\text { Moles of } \mathrm{H}_2 \mathrm{O}_2 \mathrm{in} \; 200 \mathrm{~mL} \text { of } \text{xM} \; \mathrm{H}_2 \mathrm{O}_2=\frac{200}{1000}\mathrm{\times\; x}

No. of moles of \mathrm{O}_2  produced \mathrm{=0.1 x}

Volume of \mathrm{O}_2 produced (in L)  \mathrm{=45 \times 0.1 x=10 \text { (given) }}

                                              \mathrm{x=\frac{10}{45 \times 0.1}=2.2}                                                   

Posted by

Divya Prakash Singh

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