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  • Determine the amount of   (i = 2.71 )  dissolved in 3.5 litre of water such t

Determine the amount of \mathrm{CaCl}_2  (i = 2.71 )  dissolved in 3.5 litre of water such that its osmotic pressure is 0.64 atm at 27^{\circ} \mathrm{C}

Option: 1

2.87 g


Option: 2

3.72 g


Option: 3

1.84 g


Option: 4

4.16 g


Answers (1)

\begin{aligned} & \pi=\mathrm{i\frac{ n}{V} R T} \\ \\& \pi=\mathrm{i\frac{ w}{M V} R T} \\ \\& \textup{w}= \mathrm{\frac{\pi M V}{i R T}} \end{aligned}

\begin{aligned} &= \frac{0.64 \times 111 \times 3.5}{2.71 \times 0.0821 \times 300} \\ \\& =3.72 \mathrm{~g} \end{aligned}

Posted by

Ramraj Saini

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