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  • Energy of a possible excited state of hydrogen ?Option: 1 +6.8 eVOption: 2 -6.8 eV</div

Energy of a possible excited state of hydrogen ?

Option: 1

+6.8 eV


Option: 2

-6.8 eV


Option: 3

+3.4 eV


Option: 4

-3.4 eV


Answers (1)

best_answer

\mathrm{E_n=-13.6 \frac{z^2}{n^2} \mathrm{eV}}

For 1st excited state n = 2

\mathrm{\therefore E_2=-13.6 \times \frac{1^2}{2^2}=-3.4 \mathrm{eV}}

At n=1, the population of electrons is maximum i.e at ground state. So, maximum excitation will take place from n=1 to n=2.

Hence, n=2 is the possible excited state.

Posted by

HARSH KANKARIA

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