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Equal volumes of two immiscible liquids of densities \mathrm{\rho} and \mathrm{2 p} are filled in a vessel as shown in figure. Two small holes are punched at depth \mathrm{h / 2} and \mathrm{ 3 \mathrm{~h} / 2}  from the surface of lighter liquid. If \mathrm{v}_1  and \mathrm{\mathrm{v}_2} are the velocities of a flux at these two holes, then v_1 / v_2 is :

Option: 1

\frac{1}{2 \sqrt{2}}


Option: 2

\frac{1}{2}


Option: 3

\frac{1}{4}


Option: 4

\frac{1}{\sqrt{2}}


Answers (1)

best_answer

\mathrm{\begin{aligned} & v_1=\sqrt{2 g h / 2}=\sqrt{g h} \\\\ & \text { for } v_2 \\\\ & \rho g h+2 \rho g \frac{h}{2}=\frac{1}{2} 2 \rho \cdot v_2^2 \\\\ & 2 g h=v_2^2 \\\\ & v_2=\sqrt{2 g h} \end{aligned}}

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