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Figure shows a three arm tube in which a liquid is filled upto levels of height $\mathrm{I}.$ It is now rotated at an angular frequency $\mathrm{\omega}$ about an axis passing through arm B. The angular frequency $\mathrm{\omega}$ at which level of liquid in arm B becomes zero.

Option: 1
$\mathrm{\sqrt{\frac{2 \mathrm{~g}}{3 \mathrm{l}}}}$

Option: 2
$\mathrm{\sqrt{\frac{g}{\mathrm{I}}}}$

Option: 3
$\mathrm{\sqrt{\frac{3 g}{\mathrm{I}}}}$

Option: 4
$\mathrm{\sqrt{\frac{3 \mathrm{~g}}{2 \mathrm{l}}}}$

Answers (1)

best_answer

$\mathrm{\frac{\left.\omega^2\right|^2}{2 g}=\frac{31}{2}}$

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chirag

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