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Figure shows a U-tube of uniform cross-sectional area $A$ accelerated with acceleration ' $a$ ' as shown.

If ' $d$ ' is the separation between the limbs, then the difference in the levels of the liquid in the U-tube is.
Option: 1
$\frac{\mathrm{ad}}{\mathrm{g}}$

Option: 2
$\frac{a}{g d}$

Option: 3
$\mathrm{adg}$

Option: 4
$\frac{a d g}{2}$

Answers (1)

best_answer

Using
$\tan \theta =\frac{a}{g} \\$ ,

$\begin{aligned} \frac{h}{d} & =\frac{a}{g} \\ h & =\frac{a d}{g} \end{aligned}$

Posted by

Nehul

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