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Figure shows the P − V diagram of a cyclic process ABCA, which of the following is incorrect

Option: 1

Work done in process A → B is 0.036 J


Option: 2

Work done in process B → C is −0.024 J


Option: 3

Work done in process C → A is zero


Option: 4

Work done in cycle ABCA is 0.06 J


Answers (1)

best_answer

\mathrm{\begin{aligned} & W_{A \rightarrow B}=\text { Area of } A B E D=\frac{1}{2} B C \times A C+C D \times D E \\ & =\frac{1}{2}\left(6 \times 10^{-3} \mathrm{~m}^3\right) \times 4 \mathrm{Nm}^{-2}+4 \mathrm{Nm}^{-2} \times 6 \times 10^{-3} \mathrm{~m}^3 \\ & =0.012+0.024=0.036 \mathrm{~J} \end{aligned}}

\mathrm{W_{B \rightarrow C}=\text { Area of } B C D E=-0.024 \mathrm{~J}} The negative sign shows that the work is done on the gas
\mathrm{W_{C \rightarrow A}=P \Delta V=0 \text { because } \Delta V=0} because ?V = 0
Work done in complete cycle = 0.036 − 0.024 + 0
= 0.012 J

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Anam Khan

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