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  • Find out the energy of 1 mol of a gas and its average molecular kinetic energy at <img alt="27^{\circ} \mathrm{C}" src="https://entrancecorner.oncodecogs.com/gif.latex?27%5E%7B%5Ccirc%7D%20%5C

Find out the energy of 1 mol of a gas and its average molecular kinetic energy at 27^{\circ} \mathrm{C}. Given, R=8.3 \times 10^{7} \text { erg. mol }{ }^{-1} \mathrm{~K}^{-1} \text { and } N_{A}=6.02 \times 10^{23} \mathrm{~mol}^{-1}

 

Option: 1

6.1 \times 10


Option: 2

6.4 \times 10^{-14}


Option: 3

6.3 \times 10^{-14}


Option: 4

6.2 \times 10^{-14} \mathrm{erg}


Answers (1)

best_answer

Energy of 1 mol of gas is \begin{aligned} & E=\frac{3}{2} R T=\frac{3}{2} \times\left(8-3 \times 10^{7}\right) \times 300\left[T=27^{\circ} \mathrm{C}=300 \mathrm{~K}\right]=3.735 \times 10^{10} \mathrm{er} 8 \end{aligned}

 

Average molecular kinetic energy in

\begin{aligned} & e=\frac{3}{2} \mathrm{~K} T=\frac{3}{2} \frac{R}{N_{A}} T=\frac{3}{2} \times \frac{\left(8.3 \times 10^{7}\right) \times 300}{6.02 \times 10^{23}} \\ & =6.2 \times 10^{-14} \mathrm{er} 8 \end{aligned}

 

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