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  • Find out the Kinetic energy of 2g of Nitrogen gas at 27 0C . <img alt="R= 8.3 \times 10^{7}erg/molK" src="https://entrancecorner.oncodecogs.com/gif.latex?R%3D%208.3%20%5Ctimes%

Find out the Kinetic energy of 2g of Nitrogen gas at 27 0C .

R= 8.3 \times 10^{7}erg/molK

Option: 1

270J


Option: 2

266.8J


Option: 3

280J


Option: 4

299.9J


Answers (1)

best_answer

The kinetic energy of the molecules of 1 mol of gas = \frac{3}{2}RT

Here, T= 27 0C  =  27+273 =  300K

Mass of 1mol of Nitrogen gas = 28g

So, the kinetic energy of the molecule is 2g of Nitrogen gas- 

\begin{aligned} =\frac{2}{28} \times \frac{3}{2} R T & =\frac{3}{28} R T \\ & =\frac{3}{28} \times 8.3 \times 10^7 \times 300 \\ & =2.66 \times 10^9 \mathrm{erg} \\ & =2.66 \times 10^2 \mathrm{~J} \\ & =266.8 \mathrm{~J} \end{aligned}

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shivangi.bhatnagar

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