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  • Find out the molecular kinetic energy of 1 mol of oxygen gas at STP. Given, molecular weight of oxygen = 32; density of oxygen at STP <img alt="=1.438 \cdot L^{-1}" src="https://entrancec

Find out the molecular kinetic energy of 1 mol of oxygen gas at STP. Given, molecular weight of oxygen = 32; density of oxygen at STP =1.438 \cdot L^{-1}; density of mercury =13.6 \mathrm{~g} \cdot \mathrm{cm}^{-3}

Option: 1

5.76 \times 10^{10} \mathrm{erg}


Option: 2

5.76


Option: 3

5.67 \times 10^{10} \mathrm{erg}


Option: 4

5.67


Answers (1)

best_answer

Volume of 1 mol or 32 g oxygen=\frac{32}{1.43} \mathrm{~L}=\frac{32 \times 10^{3}}{1.43} \mathrm{~cm}^{3}

 AT STP, pressure, P=76 \times 13.6 \times 981 \mathrm{dyn}, \mathrm{cm}^{-2}; temperature T=0^{\circ} \mathrm{C}=273 \mathrm{~K}

So, the molecular kinetic energy of 1 mol oxygen ga at STP 

\begin{aligned} E & =\frac{5}{2} R T=\frac{5}{2} \frac{p V}{T} T=\frac{5}{2} p V \\ & =\frac{5}{2} \times(76 \times 13.6 \times 981) \times \frac{32 \times 10^{3}}{1.43} \\ & =5.67 \times 10^{10} \mathrm{erg} \end{aligned}

Posted by

Deependra Verma

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