Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Find the dimension of the constant a in the vander waals equation <img alt="\left(P+\frac{a}{v^2}\right)(v-b)=R T" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cleft%28P&plus;%5C

Find the dimension of the constant a in the vander waals equation \left(P+\frac{a}{v^2}\right)(v-b)=R T

Option: 1

M^2 L^5 T^2


Option: 2

MLT^{-2}


Option: 3

M^2 L^5 T^6


Option: 4

ML^5 T^{-2}


Answers (1)

best_answer

The expression p+\frac{q}{v^2} shows that,

\left[\frac{a}{v^2}\right]=[p]\\ So, [a]=\left[p v^2\right]=M L^{-1} T^{-2} \cdot\left(L^3\right)^2=M L^5 T^{-2}

Posted by

Ritika Jonwal

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2025 form correction facility opens tomorrow; editable fields
anam-khan

NEET UG 2025 Registration Live: NTA NEET application deadline today; form correction from March 9
anam-khan

NEET UG 2025 application correction facility from March 9 to 11

Latest Question