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  • For a certain organ pipe, three successive resonance frequencies obtained are 425, 595, and 765 Hz. The speed of sound in air is 340 m/s. The pipe is a:Opti

For a certain organ pipe, three successive resonance frequencies obtained are 425, 595, and 765 Hz. The speed of sound in air is 340 m/s. The pipe is a:

Option: 1

Closed pipe of length 1m


Option: 2

Closed pipe of length 2m


Option: 3

Open pipe of length 1m


Option: 4

Open pipe of length 2m


Answers (1)

best_answer

F_{1}: F_{2}: F_{3} = 425 : 595 : 765 = 5 : 7 : 9

Since these are odd harmonics, the pipe is closed.

Further, 

            5 \frac{v}{4l}= 425

            l = \frac{425 * 4}{5v} = \frac{425 * 4}{5 * 340} = 1m

Posted by

Rakesh

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