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For a thermodynamic process, the P − V graph for a monoatomic gas is a straight line passing through the origin and having a positive slope. The molar heat capacity of the gas in this process is

Option: 1

R


Option: 2

2 R


Option: 3

\frac{3}{2} R


Option: 4

3 R


Answers (1)

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Since the P − V graph is a straight line with a positive slope, P ∝ V

\mathrm{\text { Or } P V^{-1}=\text { constant }}

For a process in which \mathrm{P V^n} = constant, the molar heat capacity is given by

\mathrm{C=\frac{R}{(\gamma-1)}+\frac{R}{1-n}}

\mathrm{\text { Putting } n=-1 \text { and } \gamma=\frac{5}{3} \text { (for a monoatomic gas), we have }}

\mathrm{C=\frac{R}{\left(\frac{5}{3}-1\right)}+\frac{R}{(1+1)}=\frac{3 R}{2}+\frac{R}{2}=2 R}

Posted by

Devendra Khairwa

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