Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • For the travelling harmonic wave <img alt="y(x, t) = 2.0 \cos 2\pi(10t - 0.0080x + 0.35)" src="https://entrancecorner.oncodecogs.com/gif.latex?y%28x%2C%20t%29%20%3D%202.0%20%5Ccos%202%5Cpi%2810t%20

For the travelling harmonic wave y(x, t) = 2.0 \cos 2\pi(10t - 0.0080x + 0.35) where x and y are in cm and t in second. The phase difference between oscillatory motion of two points separated by a distance 4 m will be
 

Option: 1

9.4\pi \; rad


Option: 2

2.4\pi \; rad


Option: 3

6.4\pi \; rad

 


Option: 4

7.4\pi \; rad


Answers (1)

best_answer

  Answer (3)

y(x, t) = 2.0 \cos (20 \pi t - 2 \pi \times 0.008x + 2\pi \times 0.35)

\Delta \phi =2 \pi \frac{8 \times 10^{-3}}{10^{-2}}\times 4

\Delta \phi =6.4 \pi

Posted by

sudhir kumar

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

SFI launches NEET complaint cell, demands disclosure of June 21 re-exam attendance
anam-khan

Re-NEET Answer Key 2026 LIVE: NEET OMR sheet soon at neet.nta.nic.in; objection window closes tomorrow
anam-khan

NTA reopens NEET fee refund window; submit bank details by June 30

Latest Question