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From the given electronic configuration, mark the option which will have maximum difference in first and second ionization energies.

Option: 1

\mathrm{1s^{2} 2s^{2} 2p^{6} 3s^{2}}


Option: 2

\mathrm{1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{3}}


Option: 3

\mathrm{1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{2}}


Option: 4

\mathrm{1s^{2} 2s^{2} 2p^{6} 3s^{1}}


Answers (1)

best_answer

To fulfil the condition where \mathrm{ IE_2} is significantly higher than \mathrm{ IE_1,} the atom must attain stable electronic configuration of either half-filled or fully-filled orbitals after removing one electron. Among the given options, \mathrm{1s^{2} 2s^{2} 2p^{6} 3s^{1}} is one such configuration where after the removal of one electron, it attains a stable noble gas configuration.

Hence option 4 is correct.

Posted by

Gautam harsolia

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