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  • Help me answer: A solution of sucrose (molar mass=342 g mol-1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be (Kf for water=1.86 K kg mol-1)

A solution of sucrose (molar mass=342 g mol-1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be (Kf for water=1.86 K kg mol-1)

  • Option 1)

    -0.372°C

  • Option 2)

    -0.520°C

  • Option 3)

    +0.372°C

  • Option 4)

    -0.570°C

 

Answers (1)

best_answer

As we learned in concept

Mathematical Expression of Depression in Freezing point -

\Delta T_{f}= K_{f}\: m
 

- wherein

m = molarity of solvent 

K_{f} = cryoscopic  constant

    molal depress const

Units = \frac{K-K_{g}}{mole}

 

 (\Delta T_{F})_{obs}=K_{F}\times m

                    = 1.86\times \frac{68.5}{1\times 342}

                    = 0.372^{o}C

 


Option 1)

-0.372°C

This option is correct.

Option 2)

-0.520°C

This option is incorrect.

Option 3)

+0.372°C

This option is incorrect.

Option 4)

-0.570°C

This option is incorrect.

Posted by

Aadil

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