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In the following reactions,

 

(i)\:\:CH_{3}-{{\overset {\overset {CH_{3}}{|}}{CH}}}-\underset {\overset {|}{OH}}{CH}-CH_{3-} \overset {H+/ Heat}{\longrightarrow} \underset {(Major\: products)}{A}+\underset {(Minor\: products)}{B} 

(ii)\:\:A \underset {in\:absence\:of\:peroxide}{\overset{HBr\:dark, dark}{\longrightarrow} }\:\:\:\:\:\:\underset {major product}{C}+\underset {Minor product}{D}

the major products (A) and (C) are respectively:

 

 

  • Option 1)

    CH_{2}={{\overset {\overset {CH_{3}}{|}}{C}}}-CH_{2}-CH_{3}  and

     \underset {Br}{\underset {|}{CH_{2}}}-{{\overset {\overset {CH_{3}}{|}}{CH}}}-CH_{2}-CH_{3}

  • Option 2)

    CH_{3}-{{\overset {\overset {CH_{3}}{|}}{C}}}-CH-CH_{3}  and

     CH_{3}-\underset {Br}{\underset{|}{\overset {CH_{3}}{\overset {|}{C}}}}-CH-CH_{3}

  • Option 3)

    CH_{3}-{{\overset {\overset {CH_{3}}{|}}{C}}}=CH-CH_{3} and

     CH_{3}-{{\overset {\overset {CH_{3}}{|}}{CH}}}-\underset {Br}{\underset {|}{CH}}-CH_{3}

  • Option 4)

    CH_{2}={{\overset {\overset {CH_{3}}{|}}{C}}}-CH_{2}-CH_{3}  and 

    CH_{3}-\underset {Br}{\underset {|}{\overset {CH_{3}}{\overset {|}{C}}}}-CH_{2}-CH_{3}

 

Answers (1)

best_answer

As discussed in 

 

Acidic Dehydration alcohol -

Alcohol on heating with concentrated H2SO4 form  alkenes with the elimination of one water molecule.

- wherein

 

 And,

 

Addition of Hydrogen Halide on alkene -

hydrogen halides add up to alkenes to form alkyl halides. The order of reactivity of the hydrogen halides is HI>HBr>HCl

- wherein

 

 


Option 1)

CH_{2}={{\overset {\overset {CH_{3}}{|}}{C}}}-CH_{2}-CH_{3}  and

 \underset {Br}{\underset {|}{CH_{2}}}-{{\overset {\overset {CH_{3}}{|}}{CH}}}-CH_{2}-CH_{3}

This option is incorrect.

Option 2)

CH_{3}-{{\overset {\overset {CH_{3}}{|}}{C}}}-CH-CH_{3}  and

 CH_{3}-\underset {Br}{\underset{|}{\overset {CH_{3}}{\overset {|}{C}}}}-CH-CH_{3}

This option is incorrect.

Option 3)

CH_{3}-{{\overset {\overset {CH_{3}}{|}}{C}}}=CH-CH_{3} and

 CH_{3}-{{\overset {\overset {CH_{3}}{|}}{CH}}}-\underset {Br}{\underset {|}{CH}}-CH_{3}

This option is correct.

Option 4)

CH_{2}={{\overset {\overset {CH_{3}}{|}}{C}}}-CH_{2}-CH_{3}  and 

CH_{3}-\underset {Br}{\underset {|}{\overset {CH_{3}}{\overset {|}{C}}}}-CH_{2}-CH_{3}

This option is incorrect.

Posted by

divya.saini

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