Get Answers to all your Questions

header-bg qa

A particle moves in a circle of radius 5 cm with constant speed and time period 0.2 \pi s. The acceleration of the particle is

  • Option 1)

    15m/s2

  • Option 2)

    25m/s2

  • Option 3)

    36m/s2

  • Option 4)

    5m/s2

 

Answers (1)

best_answer

As learnt in

Centripetal acceleration -

When a body is moving in a uniform circular motion, a force is responsible to change direction of its velocity.This force acts towards the centre of circle and is called centripetal force.Acceleration produced by this force is centripetal acceleration.

a= frac{v^{2}}{r}

- wherein

Figure Shows Centripetal acceleration

 

 wr = v = Kw = R\frac{2\pi }{T} = \frac{2\pi R}{T}

v= \frac{2\pi \times 0.05}{0.2\pi } = V = 0.5\ ms^{-1}

\therefore a = \frac{v^{2}}{R} = \frac{\left ( 0.5\right )^{2}}{5\times 10^{-2}} = 5\ ms^{-2}


Option 1)

15m/s2

This option is incorrect

Option 2)

25m/s2

This option is incorrect

Option 3)

36m/s2

This option is incorrect

Option 4)

5m/s2

This option is correct

Posted by

prateek

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks