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  • If a long spring is stretched 0.02 m, its potential energy is U. If the spring is stretched 0.1 m, its potential energy will beOption: 1 <i

If a long spring is stretched 0.02 m, its potential energy is U. If the spring is stretched 0.1 m, its potential energy will be

Option: 1

\frac{U}{5}

 

 


Option: 2

U


Option: 3

5U

 


Option: 4

25U


Answers (1)

best_answer

The potential energy stored in the spring is given by the formula:

U=\frac{1}{2} k x^2

where U is the potential energy, k is the spring constant, and x is the displacement of the spring from its rest position.

U\propto x^2\Rightarrow\frac{U_2}{U_1}=\left(\frac{x_2}{x_1}\right)^2=\left(\frac{0.1}{0.02}\right)^2=25

\\ \therefore U_2=25 U

Posted by

Ritika Kankaria

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