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If a ring, spherical shell, solid sphere and a cylinder of same radius are kept at the top of the inclined plane and released then the last one to reach the bottom will be 

Option: 1

Ring


Option: 2

Spherical shell 


Option: 3

Solid sphere 


Option: 4

Cylinder


Answers (1)

best_answer

a=\frac{g \sin \theta}{1+\frac{I}{m r^2}}

As,

a_{\text {sphere }}>a_{\text {shell }}>a_{\text {cylinder }}>a_{\text {ring }}

As, acceleration of the ring is least, so it will be the last to reach the bottom of the inclined plane.

Posted by

vishal kumar

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