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  • If E and G respectively denote energy and gravitational constant ,then has the dimensions of:

If E and G respectively denote energy and gravitational constant ,then \frac{E}{G} has the dimensions of:

Option: 1

\left [ M^{2} \right ]\left [ L^{-1} \right ]\left [ T^{0} \right ]


Option: 2

\left [ M \right ]\left [ L^{-1} \right ]\left [ T^{-1} \right ]


Option: 3

\left [ M \right ]\left [ L^{0} \right ]\left [ T^{0} \right ]


Option: 4

\left [ M^{2} \right ]\left [ L^{-2} \right ]\left [ T^{-1} \right ]


Answers (1)

best_answer

\left [E \right ]=[ M^{1}\: L^{2}\: T^{-2} ]

[G]=\left[\frac{F r^{2}}{m_{1} m_{2}}\right]=\left[M^{-1} L^{3} T^{-2}\right)

\left[\frac{E}{G}\right]=\left[M^{2} L^{-1} T^{0}\right]

Posted by

Sayak

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