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If $0.06\, \mathrm{M} \, \mathrm{Na}_{2} \, \mathrm{SO}_{4}$ solution at $300 \mathrm{~K}$ is found do be isotonic with $0.08\, \mathrm{M} \, \mathrm{NaCl}$ ( $100 \%$ dissociation ) solution.
What will be the degree of dissociation of sodium sulphate.
Option: 1
$94 \%$

Option: 2
$23 \%$

Option: 3
$83 \%$

Option: 4
$52 \%$

Answers (1)

best_answer

$\mathrm{i_{1}C_{1}R T=i_{2}C_{2}R T}$
$\mathrm{i_{1}C_{1}=i_{2} C_{2}}$

$\mathrm{0.6(1+2 \alpha)=0.8 \times 2}$
$\mathrm{0.6+1.2 \alpha=1.6 }$
$\mathrm{1.2 \alpha=1.6-0.6 }$
$\mathrm{1.2 \alpha=1.00}$
$\mathrm{\alpha=0.83 }$

$\mathrm{\alpha \% = 83 \% }$

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SANGALDEEP SINGH

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