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if 1\tfrac{1}{2} moles of oxygen combine with Al to form Al_{2}O_{3} , then the weight of Al used in the reaction is (Al = 27 g/mol)

Option: 1

27g


Option: 2

54g


Option: 3

49.5g


Option: 4

31g


Answers (1)

best_answer

The balanced reaction is given as 

4\ Al +3 \ O_2 \longrightarrow 2\ Al_2O_3

Now, according to reaction stoichiometry

3 moles of O_2 react with 4 moles of Al

\therefore 1.5 moles of O_2 will react with 2 moles of Al

Weight of Al will be = 27 X 2  = 54 g

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