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If the dimensions of a physical quantity are given by Ma Lb Tc, then the physical quantity will be:

Option: 1

Velocity if a = 1, b = 0, c = -1


Option: 2

Acceleration if a = 1, b = 1, c = -2


Option: 3

Force if a = 0, b = - 1, c = - 2


Option: 4

Pressure if a = 1, b = - 1, c = - 2


Answers (1)

best_answer

[velocity]=[M^0LT^{-1}]

and

[acceleration]=[M^0LT^{-2}]

and

[force]=[ma]=[MLT^{-2}]

and

[pressure]=[ \frac{force}{area}]=\frac{[MLT^{-2}]}{[L^2]}=[ML^{-1}T^{-2}]

i.e option 4 is correct

Posted by

Rishabh

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