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If the ratio of lengths, radii and Young's moduli of steel and brass wires in the figure are a, b and c respectively, then the corresponding ratio of increase in their lengths is\left(\frac{\Delta L_S}{\Delta L_B}\right) .

Option: 1

\frac{3}{2} \frac{p}{q^2 r}


Option: 2

\frac{1}{2} \frac{p}{q^2 r}


Option: 3

\frac{5}{2} \frac{p}{q^2 r}


Option: 4

\frac{7}{2} \frac{p}{q^2 r}


Answers (1)

best_answer

\begin{aligned} & T_S=3 \mathrm{mg} \\ & T_B=2 \mathrm{mg} \end{aligned}

                                      \begin{aligned} & \frac{3 m g}{A_S}=Y_S \times \frac{\Delta L_S}{L_S} \\\\ & \frac{2 m g}{A_B}=Y_B \times \frac{\Delta L_B}{L_B} \end{aligned}

 

\frac{\Delta L_S}{\Delta L_B}=\frac{3}{2} \frac{L_S}{L_B} \times \frac{A_B}{A_S} \times \frac{Y_B}{Y_S}=\frac{3}{2} \times \frac{p}{q^2 r}

 

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chirag

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