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If urea solution at $600 \mathrm{~K}$ has $\mathrm{O . P=3.81 \mathrm{~atm}}$ and glucose solution at $\mathrm{400 \mathrm{~K}}$ has $\mathrm{O . P=2.41 \mathrm{~atm}}$ . If $\mathrm{300 \mathrm{ml}}$ of first solution and $\mathrm{450 \mathrm{~mL}}$ of second solution are mixed at $\mathrm{900 \mathrm{~K}}$ then calculate O.P of resulting solution at $\mathrm{900 \, \mathrm{K}}$ .

Option: 1
$\pi=5.16 \mathrm{~atm}$

Option: 2
$\pi=3.74 \mathrm{~atm}$

Option: 3
$\pi=1.64 \mathrm{~atm}$

Option: 4
$\pi=5.66 \mathrm{~atm}$

Answers (1)

best_answer

$\mathrm{C_{\text {urea }}=\frac{3.81}{R \times 600} =0.07}$

$\mathrm{ C_{glucose }=\frac{2.41}{R \times 400} =0.07 }$

$\mathrm{ C_{\text {total }}=\frac{C_{1} V_{1}+C_{2} V_{2}}{V_{1}+V_{2}} }$

$\mathrm{ C_{\text {total }}=\frac{0.07 \times 300+0.07 \times 450}{300+450} }$

$\mathrm{ C_{\text {Total }}=0.07 }$

$\mathrm{ \pi=C R T }$
$\mathrm{ \pi=0.07 \times 0.082 \times 900}$
$\mathrm{ \pi=5.16 \mathrm{~atm}}$

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