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  • <img alt="\mathrm{The\, Reduced\, Temperature =\theta=\frac{T}{T_{A}}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BThe%5C%2C%20Reduced%5C%2C%20Temperature%20%3D%5Ctheta%3D%5Cf

\mathrm{The\, Reduced\, Temperature =\theta=\frac{T}{T_{A}}}
\mathrm{The\, Reduced\, Pressure =\Gamma=\frac{P}{P_{A}}}
\mathrm{The \, Reduced\, volume =\phi=\frac{V}{V_{A}}}

Hence, it can be said that the Reduced equation of state may be given as \mathrm{\rightarrow }

Option: 1

\left(\frac{\pi}{3}+\frac{1}{\phi}\right)(\phi-1)=\frac{8}{3} \theta


Option: 2

\left(\frac{\pi}{4}+\frac{1}{\phi}\right)(3 \theta-1)=\frac{8}{3} \phi


Option: 3

\left(\frac{M}{3}+\frac{1}{\phi}\right)(\phi-1)=\frac{8}{3} \theta


Option: 4

\left(\frac{r}{5}+\frac{1}{\phi}\right)(4 \phi-1)=\frac{8}{4} \phi


Answers (1)

best_answer

\mathrm{P=P_{A} \pi =\left(\frac{a}{27 b^{2}}\right) \pi}
\mathrm{V=V A \phi =(3 b) \phi}
\mathrm{T=T_{A} \theta =\left(\frac{8 a}{27 A_{b}}\right) \theta}

Hence, substituting in the van der wall's equation
\mathrm{\left(P+\frac{a}{v^{2}}\right)(v-b)=R T }
\mathrm{\left(n+\frac{3}{\phi^{2}}\right)(3 \phi-1)=8 \theta}

This is reduced state equation
\mathrm{ {\left[\pi+\frac{3}{\phi^{2}}\right)\left(\frac{3 \phi}{8 \theta}-\frac{1}{8 \theta}\right)=1} }
\mathrm{ {\left[\frac{\pi}{3}+\frac{1}{\phi^{2}}\right](3 \phi-1)=\frac{8}{3} \phi} }

 

Posted by

Divya Prakash Singh

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