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In a Vacuum tube an electron is continuously accelerated by applying potential difference of its debroglie wavelength is by 5%, the change in the Kinetic energy of the electron is Nearly
 

Option: 1

Decreased by 1.0 %


Option: 2

Increased by 10 %
 


Option: 3

Increased by 1 %


Option: 4

Decreased by 2.0 %


Answers (1)

best_answer

\mathrm{\lambda \; \alpha \frac{1}{\sqrt{K \cdot E}}=\sqrt{\frac{K.E_1}{K. E_2}}=\frac{\lambda_1}{\lambda_2} \; \text{or}\; \frac{\lambda_1}{1.05 \lambda_1}}

\mathrm{K \cdot E_2=(1.05)^2 K \cdot E_1}

              =\mathrm{(1.10) K.E_1}

\% \text{change in K.E}=\mathrm{\left[\frac{1.10\; K.E_{1}-K.E_{1}}{K. E_1}\right] \times 100}

                                    =\mathrm{0.1\times100=10\%}

Option (2) is the right answer.                                  

Posted by

avinash.dongre

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