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  • In the displacement method, a convex lens is placed in between an object and a screen. If the magnification in the two positions be <img alt="\mathrm{m_{1}}" src="https://entrancecorner.oncodecogs.

In the displacement method, a convex lens is placed in between an object and a screen. If the magnification in the two positions be \mathrm{m_{1}} and \mathrm{m_{2}} and the displacement of the lens between the two positions is \mathrm{X},then the focal length of the lens is :

Option: 1

\mathrm{x /\left(m_{1} \times m_{2}\right)}


Option: 2

\mathrm{x /\left|m_{1}-m_{2}\right|}


Option: 3

\mathrm{x /\left|m_{1}+m_{2}\right|}


Option: 4

\mathrm{x /\left(m_{1}-m_{2}\right)^{2}}


Answers (1)

best_answer

\mathrm{m_{1}=\frac{x_{1}}{x_{2}} \, \& \, m_{2}=\frac{x_{2}}{x_{1}} }

\mathrm{\Rightarrow m_{1}-m_{2}=\frac{x_{1} x_{2}}{x_{1}+x_{2}} }

\mathrm{\Rightarrow \quad f=\frac{x}{m_{1}-m_{2}} }

Posted by

Shailly goel

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