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  • In the given diagram, the path <img alt="\mathrm{\left ( z \right )}" src="https://entrancecorner.

In the given \mathrm{p-V}diagram, the path \mathrm{\left ( z \right )} from \mathrm{A} to \mathrm{B} is zig-zag path, but (1) is simple path. Then,

Option: 1

\mathrm{W_{1}=W_{2}}


Option: 2

\mathrm{\Delta U_{1}=\Delta U_{2}}


Option: 3

\mathrm{W_{1}>W_{2}}


Option: 4

Both (b) and (c) are true


Answers (1)

best_answer

Work done depends upon the path followed by process
So,

\mathrm{W_{1} \neq W_{2}}
Since, change in internal energy depends upon the initial and final state, it does not depend upon the path followed by the process,

\mathrm{\Delta U_{1}=\Delta U_{2}}

The area under \mathrm{p-V} diagram gives the work done by the gas. Here, path (1) is greater than path (2), so \mathrm{W_{1}>W_{2}}.Hence, option (d) is true.

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