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Light is incident normally on a diffraction grating through which the first order diffraction is seen at 32^{\circ}.The second order diffraction will be seen at

Option: 1

48^{\circ}


Option: 2

64^{\circ}


Option: 3

80^{\circ}


Option: 4

there is no second order diffraction in this case.


Answers (1)

best_answer

For a grating \mathrm{(e+d) \sin \theta_{n}=n \lambda}

\mathrm{ where (e+d)= grating \: element}
\mathrm{ \sin \theta_{n}=\frac{n \lambda}{(e+d)}}

\mathrm{ for n=1, \sin \theta_{1}=\frac{\lambda}{(e+d)}=\sin 32^{\circ}}
This is more than 0.5. Now \mathrm{ \sin \theta_{2}} will be more than \mathrm{ 2 \times 0.5}, which is not possible.

Posted by

Pankaj Sanodiya

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