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  • Light of wavelength  is incident normally on a slit of width <img alt="0.2 \mathrm{~mm}" src="https://

Light of wavelength 6328 \AA  is incident normally on a slit of width 0.2 \mathrm{~mm}. Angular width of the central maximum on the screen will be

Option: 1

0.9^{0}


Option: 2

0.18^{0}


Option: 3

0.54^{0}


Option: 4

0.36^{\circ}


Answers (1)

best_answer

a \sin \theta=\mathrm{n} \lambda

\sin \theta=\frac{\mathrm{n} \lambda}{\mathrm{a}}=\frac{6328 \times 10^{-10} \times 1}{0.2 \times 10^{-3}}

=3164 \times 10^{-6} \mathrm{rad}=0.003164 \text { radian }

\therefore \text { Angular width }=2 \theta

=2 \times 0.003164 \times \frac{180^{\circ}}{\pi}=0.36^{\circ}

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