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  • Light of wavelength is incident on a slit. First minima of the diffraction pattern is found to lie at a distanc

Light of wavelength \lambda is incident on a slit. First minima of the diffraction pattern is found to lie at a distance of 6 \mathrm{~mm} from the central maximum on a screen placed at a distance of 2 \mathrm{~m} from the slit. If slit width is 0.2 \mathrm{~mm},then wavelength of the light used will be

Option: 1

4000 \stackrel{0}{\AA}


Option: 2

6000 \AA


Option: 3

7000 \stackrel{0}{\mathrm{~A}}


Option: 4

7400 \AA


Answers (1)

best_answer

\mathrm{a \sin \theta=n \lambda}

\mathrm{ \text { a. } \frac{x}{D}=n \lambda \text { or } \lambda=\frac{a x}{n D}}

\mathrm{ \text { or } \lambda=\frac{2 \times 10^{-4} \times 6 \times 10^{-3}}{1 \times 2}=6000 \AA}

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shivangi.shekhar

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