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  •  Light of wavelength is normally incident on a slit. Angular position of second minimum from central m

 Light of wavelength 6000 \AA is normally incident on a slit. Angular position of second minimum from central maximum us 30^{\circ}. Width of the slit should be

Option: 1

12 \times 10^{-5} \mathrm{~cm}


Option: 2

18 \times 10^{-5} \mathrm{~cm}


Option: 3

24 \times 10^{-5} \mathrm{~cm}


Option: 4

36 \times 10^{-5} \mathrm{~cm}


Answers (1)

best_answer

\mathrm{a} \sin \theta=\mathrm{n} \lambda

a=\frac{n \lambda}{\sin \theta}=\frac{2 \times 6000 \times 10^{-10}}{\sin 30^{\circ}}

=\frac{2 \times 6000 \times 10^{-10}}{1 / 2}=4 \times 6000 \times 10^{-10}
=24 \times 10^{-7} \mathrm{~m}=24 \times 10^{-5} \mathrm{~cm}

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