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  • Match List -I with List -II List I List II (a) <im

Match List -I with List -II

List I List II
(a) Pcl_{5} (i) Square pyramidal
(b) SF_{6} (ii) Trigonal Planar
(c) BrF_{5} (iii) Octahedral
(d) BF_{3} (iv) Trigonal bipyramidal

Choose the corret Answer from the given below

Option: 1

(a)-(iv),(b)-(iii),(c)-(i) ,(d)-(ii)


Option: 2

(a)-(ii),(b)-(iii),(c)-(iv),(d)-(i)


Option: 3

(a)-(iii),(b)-(i),(c)-(iv),(d)-(ii)


Option: 4

(a)-(iv),(b)-(iii),(c)-(ii),(d)-(i)


Answers (1)

best_answer

To calculate hybridization 

H=\frac{V+M-Q}{2}

 

Where V is the number of valence electrons in the central atom

M is the Number of surrounding atoms 

Q is the charge present on the molecule ( if any) 
PCl_{5} has trigonal bipyramidal shape and sp3d hybridization.

H=\frac{5+5}{2}=5\quad sp^{3}d

SF_{6} has sp3d2 hybridization and octahedral geometry. 

H=\frac{6+6}{2}=6\quad sp^{3}d^{2}

BrF_{5} has sp3d2 hybridization and square pyramidal geometry. 

H=\frac{7+5}{2}=6\quad sp^{3}d^{2}

BF_{3} has sp2 hybridization and trigonal planar geometry.

H=\frac{3+3}{2}=3\quad sp^{2}

 

Hence, the correct answer is option 1.

Posted by

Pankaj Sanodiya

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