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  • Mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene <img alt="\mathrm{\left(p^{\circ}=90\right. Torr )}" src="https://entrancecorner.oncodecogs.com/gif.l

Mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene \mathrm{\left(p^{\circ}=90\right. Torr )} and toulene \mathrm{\left(p^{\circ}=110\right. Torr )} having 2.0 mole each is
 

Option: 1

0.86


Option: 2

0.12


Option: 3

0.55


Option: 4

0.48


Answers (1)

best_answer

\begin{aligned} & \mathrm{P_T}=\mathrm{X_A P _A^0+X_B P _B^{\circ}} \\ \\& \mathrm{P_T}=\frac{2}{4} \times 110+\frac{2}{4} \times 90 \\ \\& \mathrm{P_T}=\frac{220}{4}+\frac{180}{4} \\ \\& \mathrm{P_T}=55+45 \\ \\& \mathrm{P_T}=100 \end{aligned}

Mole fraction in the vapour phase

\mathrm{\frac{X_A P^{\circ} _A}{P _T}=\frac{55}{100}=0.55}

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