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Monochromatic light of wavelength 5000 \AA is incident on two slits separated by a distance of 5 \times 10^{-4} \mathrm{~m}. Interference pattern is seen on the screen placed at a distance of 1 \mathrm{~m} from the slits. A thin glass plate of thickness 1.5 \times 10^{-6} \mathrm{~m} and refractive index 1.5 is laced between one of the slits and the screen. If intensity in the absence of plate was I_{0} then new intensity at the centre of the screen will be

Option: 1

\mathrm{I}_{0}


Option: 2

2 \mathrm{I}_{0}


Option: 3

\frac{I_{0}}{2}


Option: 4

\frac{3 \mathrm{I}_{\mathrm{o}}}{4}


Answers (1)

best_answer

\mathrm{ \frac{x d}{D}=(\mu-1) t}
\mathrm{\text { or } x=\frac{(\mu-1) D t}{d}=\frac{(1.5-1) \times 1.5 \times 10^{-6} \times 1}{5 \times 10^{-4}} }

\mathrm{=1.5 \times 10^{-3} \mathrm{~m} }

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shivangi.shekhar

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