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3000 \mathrm{~J} of heat is given to a gas at constant pressure of 2 \times 10^5 \mathrm{~N} / \mathrm{m}^2. If its volume increases by 10 litres during the process. what will be the change in the internal energy of the gas
 

Option: 1

1000 \mathrm{~J}

 


Option: 2

100 \mathrm{~J}
 


Option: 3

200 \mathrm{~J}
 


Option: 4

2000\: \mathrm{J}


Answers (1)

\mathrm{\Delta Q=3000 \mathrm{~J}}

\mathrm{ P=2 \times 10^5=V_i }

\mathrm{ V_t=\left(V_i+10 \times 10^{-3}\right) }

\mathrm{ W=P d v }

\mathrm{ W=2 \times 10^5 \times 10 \times 10^{-3}=2 \times 10^3 }

\mathrm{ \Delta Q=\Delta W+\Delta U }

\mathrm{ 3000=2 \times 10^3+\Delta U }

\mathrm{ \Delta U=1000 }







 

Posted by

Kshitij

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