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  • on applying repeated electric spark on 15 mL mixture of <img alt="\mathrm{N}_2 \; \&\; \mathrm{CO}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BN%7D_2%20%5C%3B%20%5C%26%5C%

on applying repeated electric spark on 15 mL mixture of \mathrm{N}_2 \; \&\; \mathrm{CO}, it produced \mathrm{CO}_2\: \; \& \; \mathrm{NO}. For the process of combustion, 11 mL of \mathrm{O}_2 was needed. Calculate mole % of \mathrm{CO} in the mixture. (All V are measured under similar conditions).

Option: 1

5.3


Option: 2

53.33


Option: 3

4.667


Option: 4

46.67


Answers (1)

best_answer

Reactions involved are - 

\mathrm{N}_2+\mathrm{O}_2 \rightarrow 2 \mathrm{NO}

\mathrm{CO}+\frac{1}{2} \mathrm{O}_2 \rightarrow \mathrm{CO}_2

Let x mL be the volume of \mathrm{N_2} in the 15 mL mixture

Total volume of \mathrm{O_2} required \mathrm {=x+\frac{15-x}{2}=11}

\begin{aligned} & \mathrm{2 x+15-x=22 }\\ \\& \mathrm{x=22-15=7} \end{aligned}

Volume of \mathrm{CO}=15-7

                           = 8 \; \mathrm{mL}

Mol % of  \mathrm{CO}=\frac{8}{15}\times 100

                         =53.33%

Posted by

Gaurav

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