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On the horizontal surface of truck a block of mass 2 kg is placed and coefficient of friction between the block and surface is (\mu s = 0.6). If truck starts moving with acceleration 4 m/s2, then frictional force on the block will be (g = 10 m/s2)
 

Option: 1

12N


Option: 2

10\:N


Option: 3

6\:N

 


Option: 4

8\:N


Answers (1)

best_answer

Answer (4)

\\fS_{max}=\mu _s\:N\\ =o.6 \times 2 \times 10\\ =12\;N\\ F_A=ma\\ =2 \times 4\\ =8\;N\\\\ F_A<fS_{max}\\ f=F_A\\ =8A

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Rishi

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