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  • One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure. <img alt="" src="https://cdn.entrance360.com/media/uploads/2023/05/13/capturuy

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure.

The change in internal energy of the gas during the transition is:

Option: 1

-20 kJ


Option: 2

20 J


Option: 3

-12 kJ


Option: 4

20 kJ


Answers (1)

best_answer

Change in internal energy

Delta U= nfrac{f}{2}RDelta T

where

f is the degree of freedom

And also using P\mathrm{v} =nRT

we get  T = \frac{P\mathrm{v} }{nR}

\Delta U =n C_{v}\Delta T = n \frac{R}{\gamma-1}.\left ( T_{f}-T_{i} \right )

or   \Delta U = \frac{1}{\gamma-1}.\left ( nRT_{f} -nRT_{i} \right )

= \frac{P_{f}\mathrm{v} _{f}-P_{i}\mathrm{v} _{i}}{\gamma-1}

= \frac{2\times 10^{3}\times 6-5\times 10^{3}\times 4}{\frac{7}{5}-1}

= \frac{-8\times 10^{3}}{\left ( \frac{2}{5} \right )}J=-20 KJ

Posted by

vinayak

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