Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • One mole of an ideal gas is adiabatically compressed so that its temperature rises from <img alt

One mole of an ideal gas(\gamma=1.4) is adiabatically compressed so that its temperature rises from 27^{\circ} \mathrm{C} to 35^{\circ} \mathrm{C}. The change in the internal energy of the gas is (given R = 8.3 J/mole/K)

Option: 1

− 166 J


Option: 2

166 J


Option: 3

− 168 J


Option: 4

168 J


Answers (1)

best_answer

\mathrm{\Delta U=C_v \Delta T . \text { Now } C_p-C_v=R \text { or } \frac{C_p}{C_v}-1=\frac{R}{C_v}}

\mathrm{\operatorname{Or} C_v=\frac{R}{\gamma-1} \text {, where } \gamma=\frac{C_p}{C_v} \text {. Hence }}

\mathrm{\Delta U=\frac{R \Delta T}{(\gamma-1)}=\frac{8.3 \times 8}{(1.4-1)}=166 \mathrm{~J}}

Posted by

seema garhwal

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET exam stress? 17 year-old MBBS aspirant dies by suicide in Goa; police launch probe
anam-khan

NEET UG 2026 Exam LIVE: Re-NEET dates soon for MBBS, BDS admissions; registration fee refund, NTA paper leak
anam-khan

'Abolish NEET', says Tamil Nadu CM Vijay citing structural flaws; backs 12th marks for MBBS admission

Latest Question