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One mole of an ideal gas(\gamma=1.4) is adiabatically compressed so that its temperature rises from 27^{\circ} \mathrm{C} to 35^{\circ} \mathrm{C}. The change in the internal energy of the gas is (given R = 8.3 J/mole/K)

Option: 1

− 166 J


Option: 2

166 J


Option: 3

− 168 J


Option: 4

168 J


Answers (1)

best_answer

\mathrm{\Delta U=C_v \Delta T . \text { Now } C_p-C_v=R \text { or } \frac{C_p}{C_v}-1=\frac{R}{C_v}}

\mathrm{\operatorname{Or} C_v=\frac{R}{\gamma-1} \text {, where } \gamma=\frac{C_p}{C_v} \text {. Hence }}

\mathrm{\Delta U=\frac{R \Delta T}{(\gamma-1)}=\frac{8.3 \times 8}{(1.4-1)}=166 \mathrm{~J}}

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seema garhwal

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